科技行者

行者学院 转型私董会 科技行者专题报道 网红大战科技行者

知识库

知识库 安全导航

至顶网网络频道如何用SQL写出当M*N时的螺旋矩阵算法

如何用SQL写出当M*N时的螺旋矩阵算法

  • 扫一扫
    分享文章到微信

  • 扫一扫
    关注官方公众号
    至顶头条

本文将为大家介绍如何用SQL写出当M*N时的螺旋矩阵算法。

作者:赛迪网 李丝 来源:天新网 2008年3月22日

关键字: SQL Server 数据库 Mssql SQL

  • 评论
  • 分享微博
  • 分享邮件

在本页阅读全文(共6页)

     19

   20 40 18

   21 41 57 39 17

   22 42 58 70 56 38 16

   23 43 59 71 79 69 55 37 15

   24 44 60 72 80 84 78 68 54 36 14

   1 25 45 61 73 81 85 83 77 67 53 35 13

   2 26 46 62 74 82 76 66 52 34 12

   3 27 47 63 75 65 51 33 11

   4 28 48 64 50 32 10

   5 29 49 31 9

   6 30 8

   7

  -------------------------------------------------------

  想来是的, 这样你看如何?

  

  代码:--------------------------------------------------

  1 select replace(max(sys_connect_by_path(rank, ",")), ",") str

   2 from (select i, j,

   3 to_char(rank() over(order by tag), "9999") as rank

   4 from (select i,

   5 j,

   6 -- 逆时针螺旋特征码 counter-clockwise

   7 case least(j - 1, &&1 - i, &1 - j, i - 1)

   8 when j - 1 then

   9 (j - 1) || "1" || i

   10 when &1 - i then

   11 (&1 - i) || "2" || j

   12 when &1 - j then

   13 (&1 - j) || "3" || (&1 - i)

   14 when i - 1 then

   15 (i - 1) || "4" || (&1 - j)

   16 end as tag

   17 from (select level as i from dual connect by level <= &1) a,

   18 (select level as j from dual connect by level <= &1) b

   19 )

   20 )

   21 start with j = 1

   22 connect by j - 1 = prior j and i = prior i

   23 group by i

   24* order by i

  SQL> /

  输入 1 的值: 5

  原值 7: case least(j - 1, &&1 - i, &1 - j, i - 1)

  新值 7: case least(j - 1, 5 - i, 5 - j, i - 1)

  原值 10: when &1 - i then

  新值 10: when 5 - i then

  原值 11: (&1 - i) || "2" || j

  新值 11: (5 - i) || "2" || j

  原值 12: when &1 - j then

  新值 12: when 5 - j then

  原值 13: (&1 - j) || "3" || (&1 - i)

  新值 13: (5 - j) || "3" || (5 - i)

  原值 15: (i - 1) || "4" || (&1 - j)

  新值 15: (i - 1) || "4" || (5 - j)

  原值 17: from (select level as i from dual connect by level <= &1) a,

  新值 17: from (select level as i from dual connect by level <= 5) a,

  原值 18: (select level as j from dual connect by level <= &1) b

  新值 18: (select level as j from dual connect by level <= 5) b

  STR

  -----------------------------------------------------

   1 16 15 14 13

   2 17 24 23 12

   3 18 25 22 11

   4 19 20 21 10

   5 6 7 8 9

  SQL>--------------------------------------------------

  使用前, 给声明m和n并赋值

  

  代码:-------------------------------------------------

  var n number;

  var m number;

  exec :n := &n; :m=&m;

  with t as (

   select :n as n, :m as m from dual

  )

  select replace(max(sys_connect_by_path(rank, ",")), ",") str

   from (select i, j, to_char(rank() over(order by tag), "999999") as rank

   from (select i,

   j,

   -- 顺时针螺旋特征码 clockwise

   case least(i - 1, m - j, n - i, j - 1)

   when i - 1 then

   to_char(i - 1, "fm0000") || "1" ||

   to_char(j - 1, "fm0000")

   when m - j then

   to_char(m - j, "fm0000") || "2" ||

   to_char(i - 1, "fm0000")

   when n - i then

   to_char(n - i, "fm0000") || "3" ||

   to_char(m - j, "fm0000")

   when j - 1 then

   to_char(j - 1, "fm0000") || "4" ||

   to_char(n - i, "fm0000")

   end as tag

   from (select n, level as i from t connect by level <= n) a,

   (select m, level as j from t connect by level <= m) b))

   start with j = 1

  connect by j - 1 = prior j and i = prior i

   group by i

  --------------------------------------------------------------

    • 评论
    • 分享微博
    • 分享邮件
    邮件订阅

    如果您非常迫切的想了解IT领域最新产品与技术信息,那么订阅至顶网技术邮件将是您的最佳途径之一。

    重磅专题
    往期文章
    最新文章